Exercise 1.41. Define a procedure double that takes a procedure of one argument as argument and returns a procedure that applies the original procedure twice. For example, if inc is a procedure that adds 1 to its argument, then (double inc) should be a procedure that adds 2. What value is returned by

 
(((double (double double)) inc) 5)
 
(define (double f)
  (lambda (x)
    (f (f x))))
 
(((double (double double)) inc) 5)